what is the equation of the vertical asymptote of $f(x)=2log_2(x + 1)-3$? enter your answer in the box…
what is the equation of the vertical asymptote of $f(x)=2log_2(x + 1)-3$? enter your answer in the box. $x=square$
Answer
Explanation:
Step1: Recall log - function property
The domain of the logarithmic function $y = \log_a(u)$ is $u>0$. For the function $f(x)=2\log_2(x + 1)-3$, we set $u=x + 1$.
Step2: Find the value that makes the argument zero
We solve the equation $x+1 = 0$ to find the vertical - asymptote. Subtract 1 from both sides of the equation $x+1=0$, we get $x=-1$.
Answer:
$x=-1$