evaluate the definite integral below. ∫₁⁵ -3x² dx

evaluate the definite integral below. ∫₁⁵ -3x² dx
Answer
Explanation:
Step1: Find antiderivative
The antiderivative of $-3x^{2}$ is $-3\times\frac{x^{3}}{3}=-x^{3}$ using the power - rule for integration $\int x^{n}dx=\frac{x^{n + 1}}{n+1}+C$ ($n\neq - 1$).
Step2: Apply fundamental theorem of calculus
$\int_{1}^{5}-3x^{2}dx=\left[-x^{3}\right]_{1}^{5}=-(5^{3})-(-(1^{3}))$.
Step3: Calculate the result
$-(5^{3})-(-(1^{3}))=-125 + 1=-124$.
Answer:
$-124$