evaluate the expression.\narccos\\left(\\cos\\frac{2\\pi}{3}\\right)\n\na. \\frac{2\\pi}{3}\nb…

evaluate the expression.\narccos\\left(\\cos\\frac{2\\pi}{3}\\right)\n\na. \\frac{2\\pi}{3}\nb. \\frac{\\pi}{6}\nc. \\frac{7\\pi}{6}\nd. \\frac{\\pi}{3}

evaluate the expression.\narccos\\left(\\cos\\frac{2\\pi}{3}\\right)\n\na. \\frac{2\\pi}{3}\nb. \\frac{\\pi}{6}\nc. \\frac{7\\pi}{6}\nd. \\frac{\\pi}{3}

Answer

Explanation:

Step1: Recall the property of inverse cosine function

The property of the inverse cosine function (y = \arccos(x)) is that (\arccos(\cos\theta)=\theta) when (0\leq\theta\leq\pi).

Step2: Check the range of (\frac{2\pi}{3})

Since (0\leq\frac{2\pi}{3}\leq\pi), we can directly use the property (\arccos(\cos\theta)=\theta). Here (\theta = \frac{2\pi}{3}).

Answer:

A. (\frac{2\pi}{3})