evaluate the following indefinite integral.\n∫(1 + 8t^5)/(3t)dt\n∫(1 + 8t^5)/(3t)dt = \n(use parentheses to…

evaluate the following indefinite integral.\n∫(1 + 8t^5)/(3t)dt\n∫(1 + 8t^5)/(3t)dt = \n(use parentheses to clearly denote the argument of each function.)
Answer
Explanation:
Step1: Split the fraction
$\int\frac{1 + 8t^{5}}{3t}dt=\int(\frac{1}{3t}+\frac{8t^{5}}{3t})dt=\int(\frac{1}{3t}+\frac{8}{3}t^{4})dt$
Step2: Integrate term - by - term
$\int(\frac{1}{3t}+\frac{8}{3}t^{4})dt=\frac{1}{3}\int\frac{1}{t}dt+\frac{8}{3}\int t^{4}dt$
Step3: Apply integration formulas
We know that $\int\frac{1}{t}dt=\ln|t|+C_1$ and $\int t^{n}dt=\frac{t^{n + 1}}{n+1}+C_2$ ($n\neq - 1$). So, $\frac{1}{3}\int\frac{1}{t}dt+\frac{8}{3}\int t^{4}dt=\frac{1}{3}\ln|t|+\frac{8}{3}\times\frac{t^{5}}{5}+C$
Step4: Simplify the result
$\frac{1}{3}\ln|t|+\frac{8}{15}t^{5}+C$
Answer:
$\frac{1}{3}\ln|t|+\frac{8}{15}t^{5}+C$