evaluate $lim_{x\rightarrow3}\frac{x^{2}-9}{x + 1}$\nundefined\n4\n0\n1\n3
evaluate $lim_{x\rightarrow3}\frac{x^{2}-9}{x + 1}$\nundefined\n4\n0\n1\n3
Answer
Explanation:
Step1: Substitute x = 3
Substitute x = 3 into $\frac{x^{2}-9}{x + 1}$. When x = 3, $x^{2}-9=3^{2}-9=9 - 9=0$ and $x + 1=3+1 = 4$.
Step2: Calculate the limit value
The limit $\lim_{x\rightarrow3}\frac{x^{2}-9}{x + 1}=\frac{0}{4}=0$.
Answer:
0