evaluate y = ln (x - 2) for the following values of x. round to the nearest thousandth. x = 3, y = x = 4, y…

evaluate y = ln (x - 2) for the following values of x. round to the nearest thousandth. x = 3, y = x = 4, y ≈ x = 6, y ≈ done

evaluate y = ln (x - 2) for the following values of x. round to the nearest thousandth. x = 3, y = x = 4, y ≈ x = 6, y ≈ done

Answer

Explanation:

Step1: Substitute x = 3

Substitute x = 3 into y = ln(x - 2). We get y = ln(3 - 2)=ln(1). Since ln(1)=0, when x = 3, y = 0.

Step2: Substitute x = 4

Substitute x = 4 into y = ln(x - 2). We get y = ln(4 - 2)=ln(2). Using a calculator, ln(2)≈0.693.

Step3: Substitute x = 6

Substitute x = 6 into y = ln(x - 2). We get y = ln(6 - 2)=ln(4). Since ln(4)=2ln(2), and using the value of ln(2)≈0.693, then y = 2×0.693 = 1.386.

Answer:

When x = 3, y = 0 When x = 4, y ≈ 0.693 When x = 6, y ≈ 1.386