evaluate $y = ln(x - 2)$ for the following values of $x$. round to the nearest thousandth.\n$x = 3…

evaluate $y = ln(x - 2)$ for the following values of $x$. round to the nearest thousandth.\n$x = 3, y=square$\n$x = 4, yapproxsquare$\n$x = 6, yapproxsquare$\ndone

evaluate $y = ln(x - 2)$ for the following values of $x$. round to the nearest thousandth.\n$x = 3, y=square$\n$x = 4, yapproxsquare$\n$x = 6, yapproxsquare$\ndone

Answer

Explanation:

Step1: Substitute x = 3

Substitute x = 3 into y = ln(x - 2). $y=\ln(3 - 2)=\ln(1)$ Since $\ln(1)=0$, when x = 3, y = 0.

Step2: Substitute x = 4

Substitute x = 4 into y = ln(x - 2). $y=\ln(4 - 2)=\ln(2)$ Using a calculator, $\ln(2)\approx0.693$.

Step3: Substitute x = 6

Substitute x = 6 into y = ln(x - 2). $y=\ln(6 - 2)=\ln(4)$ Using a calculator, $\ln(4)\approx1.386$.

Answer:

When x = 3, y = 0; when x = 4, y ≈ 0.693; when x = 6, y ≈ 1.386.