evaluate $y = ln(x - 2)$ for the following values of $x$. round to the nearest thousandth.\n$x = 3,y=\n$ $x…
evaluate $y = ln(x - 2)$ for the following values of $x$. round to the nearest thousandth.\n$x = 3,y=\n$ $x = 4,yapprox\n$ $x = 6,yapprox$
Answer
Explanation:
Step1: Substitute x = 3
Substitute x = 3 into y = ln(x - 2). We get y = ln(3 - 2)=ln(1). Since ln(1)=0, when x = 3, y = 0.
Step2: Substitute x = 4
Substitute x = 4 into y = ln(x - 2). We get y = ln(4 - 2)=ln(2). Using a calculator, ln(2)≈0.693.
Step3: Substitute x = 6
Substitute x = 6 into y = ln(x - 2). We get y = ln(6 - 2)=ln(4). Since ln(4)=2ln(2), and ln(2)≈0.693, then ln(4)≈2×0.693 = 1.386.
Answer:
When x = 3, y = 0 When x = 4, y≈0.693 When x = 6, y≈1.386