find $g(-3)$. $g(x)$ $h(x)=2x^{2}+5x - 2$
find $g(-3)$. $g(x)$ $h(x)=2x^{2}+5x - 2$
Answer
Explanation:
Step1: Determine the equation of the line (g(x))
The line (g(x)) passes through the points ((0,5)) (y - intercept (b = 5)) and ((- 5,0)). The slope (m) of the line is given by the formula (m=\frac{y_2 - y_1}{x_2 - x_1}). Using ((x_1,y_1)=(0,5)) and ((x_2,y_2)=(-5,0)), we have (m=\frac{0 - 5}{-5-0}=\frac{-5}{-5}=1). The equation of the line in slope - intercept form (y = mx + b) is (g(x)=x + 5).
Step2: Evaluate (g(x)) at (x=-3)
Substitute (x=-3) into (g(x)=x + 5). (g(-3)=-3 + 5)
Answer:
(2)