find f(x).\nf(x)=9e^{-3x}\nf(x)=□
find f(x).\nf(x)=9e^{-3x}\nf(x)=□
Answer
Explanation:
Step1: Recall derivative rule
The derivative of $e^{u}$ is $e^{u}\cdot u'$. Here $u = - 3x$ and the function is $y = 9e^{-3x}$.
Step2: Differentiate
$y'=9\cdot e^{-3x}\cdot(-3)$.
Answer:
$-27e^{-3x}$