find the absolute extrema of the function (if any exist) on each interval. (if an answer does not exist…

find the absolute extrema of the function (if any exist) on each interval. (if an answer does not exist, enter dne.\n$f(x)=x^{2}-8x$\n(a) $-1,8$\nminimum $(x,y)=$\nmaximum $(x,y)=$\n(b) $(4,9$\nminimum $(x,y)=$\nmaximum $(x,y)=$\n(c) $(0,8)$\nminimum $(x,y)=$\nmaximum $(x,y)=$\n(d) $4,10)$\nminimum $(x,y)=$\nmaximum $(x,y)=$
Answer
Explanation:
Step1: Find the derivative of the function
The function is (f(x)=x^{2}-8x). Using the power rule ((x^n)^\prime = nx^{n - 1}), the derivative (f^\prime(x)=2x - 8).
Step2: Find the critical points
Set (f^\prime(x)=0), so (2x-8 = 0). Solving for (x) gives (x = 4).
Part (a) Interval ([-1,8])
Step1: Evaluate the function at critical and endpoints
- (f(-1)=(-1)^{2}-8\times(-1)=1 + 8=9)
- (f(4)=4^{2}-8\times4=16-32=-16)
- (f(8)=8^{2}-8\times8=64 - 64=0)
Part (b) Interval ((4,9])
Step1: Analyze the behavior of the function
Since (f^\prime(x)=2x - 8), for (x>4), (f^\prime(x)>0) (function is increasing).
- (f(4)) is not in the open - ended part of the interval ((4,9]). Evaluate (f(9)=9^{2}-8\times9=81-72 = 9)
Part (c) Interval ((0,8))
Step1: Analyze the behavior of the function
Since (f^\prime(x)=2x - 8), (f(x)) is decreasing on ((0,4)) (because (f^\prime(x)<0) when (x\in(0,4))) and increasing on ((4,8)) (because (f^\prime(x)>0) when (x\in(4,8))). But the endpoints (x = 0) and (x = 8) are not included.
Part (d) Interval ([4,10))
Step1: Analyze the behavior of the function
Since (f^\prime(x)=2x - 8), for (x\geq4), (f^\prime(x)\geq0) (function is non - decreasing). (f(4)=4^{2}-8\times4=-16) and (f(10)=10^{2}-8\times10=100 - 80 = 20) (but (x = 10) is not included)
Answer:
(a) minimum ((x,y)=(4,-16)) maximum ((x,y)=(-1,9))
(b) minimum DNE maximum ((x,y)=(9,9))
(c) minimum DNE maximum DNE
(d) minimum ((x,y)=(4,-16)) maximum DNE