find the absolute maximum and minimum, if either exists, for the function on the indicated…

find the absolute maximum and minimum, if either exists, for the function on the indicated interval.\nf(x)=(x - 3)(x - 7)^{3}+3\n(a)0,5 (b)2,9 (c)5,8\n(a) find the absolute maximum. select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.\na. the absolute maximum is 1032 at x = 0.\n(use a comma to separate answers as needed.)\nb. there is no absolute maximum.\nfind the absolute minimum. select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.\na. the absolute minimum is at x=\n(use a comma to separate answers as needed.)\nb. there is no absolute minimum.

find the absolute maximum and minimum, if either exists, for the function on the indicated interval.\nf(x)=(x - 3)(x - 7)^{3}+3\n(a)0,5 (b)2,9 (c)5,8\n(a) find the absolute maximum. select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.\na. the absolute maximum is 1032 at x = 0.\n(use a comma to separate answers as needed.)\nb. there is no absolute maximum.\nfind the absolute minimum. select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.\na. the absolute minimum is at x=\n(use a comma to separate answers as needed.)\nb. there is no absolute minimum.

Answer

Explanation:

Step1: Find the derivative of (f(x))

Use the product rule ((uv)^\prime = u^\prime v+uv^\prime), where (u=(x - 3)) and (v=(x - 7)^3). (u^\prime=1), (v^\prime = 3(x - 7)^2) (f^\prime(x)=(x - 7)^3+3(x - 3)(x - 7)^2=(x - 7)^2[(x - 7)+3(x - 3)]=(x - 7)^2(4x-16)=4(x - 7)^2(x - 4))

Step2: Find the critical points in the interval ([0,5])

Set (f^\prime(x)=0), then (x = 4) or (x = 7). But (x = 7\notin[0,5]) So the critical point in ([0,5]) is (x = 4)

Step3: Evaluate (f(x)) at the endpoints and critical point

  • (f(0)=(0 - 3)(0 - 7)^3+3=(-3)\times(-343)+3=1032)
  • (f(4)=(4 - 3)(4 - 7)^3+3=(1)\times(-27)+3=-24)
  • (f(5)=(5 - 3)(5 - 7)^3+3=(2)\times(-8)+3=-13)

Answer:

The absolute minimum is (-24) at (x = 4)