find the absolute value.\n|9 - 2i|\n√?

Explanation:

Step1: Recall the formula for the absolute value of a complex number ( z = a + bi ), which is ( |z|=\sqrt{a^{2}+b^{2}} ).

For the complex number ( 9 - 2i ), we have ( a = 9 ) and ( b=- 2 ).

Step2: Substitute ( a = 9 ) and ( b = - 2 ) into the formula ( a^{2}+b^{2} ).

Calculate ( a^{2}+b^{2}=9^{2}+(-2)^{2}=81 + 4=85 ).

Answer:

( 85 ) (So the value inside the square root is ( 85 ))