find the average rate of change of $g(x)=-x^{4}+16$ over the interval $1,3$. write your answer as an…

find the average rate of change of $g(x)=-x^{4}+16$ over the interval $1,3$. write your answer as an integer, fraction, or decimal rounded to the nearest tenth. simplify any fractions.
Answer
Explanation:
Step1: Recall average - rate - of - change formula
The average rate of change of a function $y = g(x)$ over the interval $[a,b]$ is $\frac{g(b)-g(a)}{b - a}$. Here, $a = 1$, $b = 3$, and $g(x)=-x^{4}+16$.
Step2: Calculate $g(3)$
Substitute $x = 3$ into $g(x)$: $g(3)=-(3)^{4}+16=-81 + 16=-65$.
Step3: Calculate $g(1)$
Substitute $x = 1$ into $g(x)$: $g(1)=-(1)^{4}+16=-1 + 16 = 15$.
Step4: Calculate the average rate of change
$\frac{g(3)-g(1)}{3 - 1}=\frac{-65-15}{2}=\frac{-80}{2}=-40$.
Answer:
$-40$