find the critical point and determine if the function is increasing or decreasing on the given intervals.\ny…

find the critical point and determine if the function is increasing or decreasing on the given intervals.\ny = -x^2 + 8x + 5\ncritical point: c =\nthe function is:\non (-∞, c).\non (c, ∞).
Answer
Explanation:
Step1: Find the derivative
Differentiate $y = -x^{2}+8x + 5$ using power - rule. The derivative $y'=-2x + 8$.
Step2: Find the critical point
Set $y' = 0$. So, $-2x+8 = 0$. Solving for $x$ gives $2x=8$, then $x = 4$. So the critical point $c = 4$.
Step3: Test the intervals
For the interval $(-\infty,4)$, choose a test - point, say $x = 3$. Then $y'(3)=-2\times3 + 8=2>0$. So the function is increasing on $(-\infty,4)$. For the interval $(4,\infty)$, choose a test - point, say $x = 5$. Then $y'(5)=-2\times5 + 8=-2<0$. So the function is decreasing on $(4,\infty)$.
Answer:
Critical point: $c = 4$ The function is: increasing on $(-\infty,4)$ decreasing on $(4,\infty)$