find the domain and range for the cube root function. state the x- and y-intercepts, if they…

find the domain and range for the cube root function. state the x- and y-intercepts, if they exist.\n$f(x)=\\sqrt3{8x}$\nthe domain of $y = f(x)$ is $\\square$. (type an inequality or a compound inequality.)
Answer
Explanation:
Step1: Analyze cube root domain
Unlike square roots, cube roots are defined for all real numbers, since we can take the cube of any positive, negative, or zero real number. The function $f(x)=\sqrt[3]{8x}$ has no restrictions on the input $x$.
Step2: Define domain inequality
All real numbers can be written as the inequality $-\infty < x < \infty$.
Step3: Find x-intercept
Set $f(x)=0$, solve $\sqrt[3]{8x}=0$. Cube both sides: $8x=0$, so $x=0$. The x-intercept is $(0,0)$.
Step4: Find y-intercept
Set $x=0$, calculate $f(0)=\sqrt[3]{8*0}=0$. The y-intercept is $(0,0)$.
Step5: Analyze cube root range
Cube root functions output all real numbers, since for any real number $y$, we can find an $x$ such that $\sqrt[3]{8x}=y$ (solve for $x$: $x=\frac{y^3}{8}$, which is defined for all real $y$).
Answer:
- Domain of $y=f(x)$: $-\infty < x < \infty$
- Range of $y=f(x)$: $-\infty < y < \infty$
- x-intercept: $(0, 0)$
- y-intercept: $(0, 0)$