find the equation of the vertical asymptote $f(x)=\\log(x + 2)$
find the equation of the vertical asymptote $f(x)=\\log(x + 2)$
Answer
Explanation:
Step1: Recall the domain of logarithmic function
The domain of (y = \log(u)) is (u>0). For (y=\log(x + 2)), we set (x+2>0).
Step2: Solve the inequality for (x)
Subtract (2) from both sides of (x + 2>0). We get (x>- 2). As (x) approaches (-2) from the right ((x\to - 2^{+})), the function (y = \log(x + 2)) has a vertical asymptote.
Answer:
(x=-2)