find the exact value. \ncos\\frac{11\\pi}{6}\ntype + or -\n?\\frac{\\sqrt{}}{}

Explanation:

Step1: Find the reference angle

The angle (\frac{11\pi}{6}) is in the fourth - quadrant. The reference angle (\theta_{r}=2\pi-\frac{11\pi}{6}=\frac{\pi}{6}).

Step2: Determine the sign

In the fourth - quadrant, cosine is positive.

Step3: Evaluate using the reference angle

We know that (\cos\theta=\cos\theta_{r}) for (\theta = \frac{11\pi}{6}) and (\theta_{r}=\frac{\pi}{6}), and (\cos\frac{\pi}{6}=\frac{\sqrt{3}}{2})

Answer:

(+\frac{\sqrt{3}}{2})