find the exact value of $\\cos\\left(-\\frac{5\\pi}{4}\\right)$.\n$\\cos\\left(-\\frac{5\\pi}{4}\\right)=\\sq…

find the exact value of $\\cos\\left(-\\frac{5\\pi}{4}\\right)$.\n$\\cos\\left(-\\frac{5\\pi}{4}\\right)=\\square$
Answer
Explanation:
Step1: Use the cosine even - function property
The cosine function is even, i.e., (\cos(-x)=\cos(x)). So, (\cos\left(-\frac{5\pi}{4}\right)=\cos\left(\frac{5\pi}{4}\right)).
Step2: Rewrite the angle
We can rewrite (\frac{5\pi}{4}) as (\pi+\frac{\pi}{4}). Then, by the cosine of a sum formula (\cos(A + B)=\cos A\cos B-\sin A\sin B) (where (A=\pi) and (B = \frac{\pi}{4})), (\cos\left(\pi+\frac{\pi}{4}\right)=\cos\pi\cos\frac{\pi}{4}-\sin\pi\sin\frac{\pi}{4}). Since (\cos\pi=- 1), (\sin\pi = 0), and (\cos\frac{\pi}{4}=\sin\frac{\pi}{4}=\frac{\sqrt{2}}{2}), we have (\cos\left(\pi+\frac{\pi}{4}\right)=(-1)\times\frac{\sqrt{2}}{2}-0\times\frac{\sqrt{2}}{2}).
Step3: Calculate the value
(\cos\left(\pi+\frac{\pi}{4}\right)=-\frac{\sqrt{2}}{2}).
Answer:
(-\frac{\sqrt{2}}{2})