find the exact value of the expression.\n(\tan^{-1}(cot\frac{2pi}{3}))\nselect the correct choice and, if…

find the exact value of the expression.\n(\tan^{-1}(cot\frac{2pi}{3}))\nselect the correct choice and, if necessary, fill in the answer box to complete your choice.\n(\bigcirc) a. (\tan^{-1}(cot\frac{2pi}{3})=)\n(simplify your answer. type an exact answer, using (pi) as needed. use integers or fractions for any numbers in the expression.)\n(\bigcirc) b. there is no solution.
Answer
Explanation:
Step1: Calculate the value of (\cot\frac{2\pi}{3})
We know that (\cot\theta=\frac{\cos\theta}{\sin\theta}). For (\theta = \frac{2\pi}{3}), (\cos\frac{2\pi}{3}=-\frac{1}{2}) and (\sin\frac{2\pi}{3}=\frac{\sqrt{3}}{2}). So, (\cot\frac{2\pi}{3}=\frac{\cos\frac{2\pi}{3}}{\sin\frac{2\pi}{3}}=\frac{-\frac{1}{2}}{\frac{\sqrt{3}}{2}}=-\frac{1}{\sqrt{3}})
Step2: Calculate the value of (\tan^{- 1}\left(-\frac{1}{\sqrt{3}}\right))
Let (y = \tan^{-1}x), where (x\in(-\infty,\infty)) and (y\in\left(-\frac{\pi}{2},\frac{\pi}{2}\right)). We know that (\tan\left(-\frac{\pi}{6}\right)=-\frac{1}{\sqrt{3}})
Answer:
(\tan^{-1}\left(\cot\frac{2\pi}{3}\right)=-\frac{\pi}{6})