find the exact value or type \undefined\ tan 30°

Explanation:

Step1: Recall the trigonometric value

We know that (\tan\theta=\frac{\sin\theta}{\cos\theta}). For (\theta = 30^{\circ}), (\sin30^{\circ}=\frac{1}{2}) and (\cos30^{\circ}=\frac{\sqrt{3}}{2}).

Step2: Calculate (\tan30^{\circ})

[ \begin{align*} \tan30^{\circ}&=\frac{\sin30^{\circ}}{\cos30^{\circ}}\ &=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\ &=\frac{1}{\sqrt{3}}\ &=\frac{\sqrt{3}}{3} \end{align*} ]

Answer:

The numerator (the value under the square - root) is (3) and the denominator is (3).