find the given limit.\n lim_{x\rightarrow3}(-x^{2}+3x - 8)\n lim_{x\rightarrow3}(-x^{2}+3x - 8)=square…
find the given limit.\n lim_{x\rightarrow3}(-x^{2}+3x - 8)\n lim_{x\rightarrow3}(-x^{2}+3x - 8)=square \text{ (simplify your answer.)}
Answer
Explanation:
Step1: Substitute x = 3
Substitute x = 3 into -x² + 3x - 8. [ \begin{align*} &-(3)^{2}+3\times3 - 8\ =&-9 + 9-8 \end{align*} ]
Step2: Simplify the expression
[ \begin{align*} -9 + 9-8&=( - 9+9)-8\ &=0 - 8\ &=-8 \end{align*} ]
Answer:
-8