find the horizontal asymptote.\ny = \\frac{3x + 12}{x - 6}\ny = ?

find the horizontal asymptote.\ny = \\frac{3x + 12}{x - 6}\ny = ?

find the horizontal asymptote.\ny = \\frac{3x + 12}{x - 6}\ny = ?

Answer

Answer:

$y = 3$

Explanation:

Step1: Identify degrees of polynomials

The degree of the numerator $3x + 12$ is 1 and of the denominator $x - 6$ is 1.

Step2: Use horizontal - asymptote rule

When the degrees of the numerator and denominator are equal, the horizontal asymptote is $y=\frac{a}{b}$, where $a$ is the leading - coefficient of the numerator and $b$ is the leading - coefficient of the denominator. Here, $a = 3$ and $b = 1$, so $y=\frac{3}{1}=3$.