find the horizontal asymptote.\ny = \\frac{3x + 27}{x - 9}\ny = ?

find the horizontal asymptote.\ny = \\frac{3x + 27}{x - 9}\ny = ?

find the horizontal asymptote.\ny = \\frac{3x + 27}{x - 9}\ny = ?

Answer

Explanation:

Step1: Identify degrees of polynomials

The degree of the numerator $3x + 27$ is 1 and the degree of the denominator $x - 9$ is 1.

Step2: Use horizontal - asymptote rule

When the degrees of the numerator and denominator are equal, the horizontal asymptote $y$ is the ratio of the leading - coefficients. The leading coefficient of the numerator is 3 and the leading coefficient of the denominator is 1.

Answer:

$y = 3$