find the horizontal asymptote.\ny = \\frac{4x - 12}{x + 2}\ny = ?

find the horizontal asymptote.\ny = \\frac{4x - 12}{x + 2}\ny = ?
Answer
Explanation:
Step1: Check degrees of polynomials
The degree of the numerator $4x - 12$ is 1 and the degree of the denominator $x + 2$ is 1.
Step2: Use horizontal - asymptote rule for equal - degree
When the degrees of the numerator and denominator of a rational function are equal, the horizontal asymptote is $y=\frac{a}{b}$, where $a$ is the leading coefficient of the numerator and $b$ is the leading coefficient of the denominator. Here, $a = 4$ and $b = 1$.
Answer:
$y = 4$