find the horizontal asymptote.\ny = \\frac{6x - 18}{x + 9}\ny = ?

find the horizontal asymptote.\ny = \\frac{6x - 18}{x + 9}\ny = ?

find the horizontal asymptote.\ny = \\frac{6x - 18}{x + 9}\ny = ?

Answer

Explanation:

Step1: Check degrees of polynomials

The degree of the numerator $6x - 18$ is 1 and the degree of the denominator $x + 9$ is 1.

Step2: Use horizontal - asymptote rule

When the degrees of the numerator and denominator are equal, the horizontal asymptote is $y=\frac{a}{b}$, where $a$ is the leading - coefficient of the numerator and $b$ is the leading - coefficient of the denominator. Here, $a = 6$ and $b = 1$.

Answer:

$y = 6$