find the horizontal asymptote.\ny = \\frac{7x + 21}{x - 3}\ny = ?

find the horizontal asymptote.\ny = \\frac{7x + 21}{x - 3}\ny = ?

find the horizontal asymptote.\ny = \\frac{7x + 21}{x - 3}\ny = ?

Answer

Answer:

$y = 7$

Explanation:

Step1: Check degrees of polynomials

The degree of the numerator $7x + 21$ is 1 and the degree of the denominator $x - 3$ is 1.

Step2: Use horizontal - asymptote rule

When the degrees of the numerator and denominator are equal, the horizontal asymptote is $y=\frac{a}{b}$, where $a$ is the leading coefficient of the numerator and $b$ is the leading coefficient of the denominator. Here, $a = 7$ and $b = 1$, so $y=\frac{7}{1}=7$.