find the horizontal asymptote.\ny = \\frac{9x - 18}{x + 3}\ny = ?
find the horizontal asymptote.\ny = \\frac{9x - 18}{x + 3}\ny = ?
Answer
Explanation:
Step1: Identify degrees of polynomials
The degree of the numerator $9x - 18$ is 1 and the degree of the denominator $x+3$ is 1.
Step2: Use horizontal - asymptote rule
When the degrees of the numerator and denominator are equal, the horizontal asymptote $y$ is the ratio of the leading - coefficients. The leading coefficient of the numerator is 9 and the leading coefficient of the denominator is 1. $y=\frac{9}{1}$
Answer:
$y = 9$