find the maximum and minimum values of the function over the given interval. f(x) = √x - 4, 0 ≤ x ≤ 9 a…

Explanation:

Step1: Analyze the function's behavior

The function is $f(x)=\sqrt{x}-4$, and the square - root function $y = \sqrt{x}$ is an increasing function for $x\geq0$.

Step2: Find the value at the lower - bound of the interval

When $x = 0$, substitute $x$ into $f(x)$: $f(0)=\sqrt{0}-4=- 4$.

Step3: Find the value at the upper - bound of the interval

When $x = 9$, substitute $x$ into $f(x)$: $f(9)=\sqrt{9}-4=3 - 4=-1$.

Answer:

C. minimum: -4, maximum: -1