find the period. y = 1/9 sec(2πx - π)

Explanation:

Step1: Recall secant - function period formula

The general form of a secant function is $y = A\sec(Bx - C)+D$, and its period is given by $T=\frac{2\pi}{|B|}$.

Step2: Identify the value of B

For the function $y=\frac{1}{9}\sec(2\pi x-\pi)$, we have $B = 2\pi$.

Step3: Calculate the period

Substitute $B = 2\pi$ into the period formula $T=\frac{2\pi}{|B|}$. Then $T=\frac{2\pi}{|2\pi|}=1$.

Answer:

1