find the slope of the functions graph at the given point. then find an equation for the line tangent to the…

find the slope of the functions graph at the given point. then find an equation for the line tangent to the graph there. f(x)=x^2 + 1, (5,26)\nwhat is the slope of the functions graph at the given point?\nm = (simplify your answer.)
Answer
Explanation:
Step1: Find the derivative of the function
The derivative of $f(x)=x^{2}+1$ using the power - rule $\frac{d}{dx}(x^{n}) = nx^{n - 1}$ is $f^\prime(x)=2x$.
Step2: Evaluate the derivative at the given x - value
We want to find the slope at the point $(5,26)$. Substitute $x = 5$ into $f^\prime(x)$. So $m=f^\prime(5)=2\times5 = 10$.
Step3: Find the equation of the tangent line
Use the point - slope form of a line $y - y_{1}=m(x - x_{1})$, where $(x_{1},y_{1})=(5,26)$ and $m = 10$. $y-26=10(x - 5)$ $y-26=10x-50$ $y=10x - 24$
Answer:
The slope of the function's graph at the given point is $m = 10$. The equation of the tangent line is $y=10x - 24$.