find the slope of the functions graph at the given point. then find an equation for the line tangent to the…

find the slope of the functions graph at the given point. then find an equation for the line tangent to the graph there. f(x)=x^2 + 1, (5,26)\nwhat is the slope of the functions graph at the given point?\nm = (simplify your answer.)

find the slope of the functions graph at the given point. then find an equation for the line tangent to the graph there. f(x)=x^2 + 1, (5,26)\nwhat is the slope of the functions graph at the given point?\nm = (simplify your answer.)

Answer

Explanation:

Step1: Find the derivative of the function

The derivative of $f(x)=x^{2}+1$ using the power - rule $\frac{d}{dx}(x^{n}) = nx^{n - 1}$ is $f^\prime(x)=2x$.

Step2: Evaluate the derivative at the given x - value

We want to find the slope at the point $(5,26)$. Substitute $x = 5$ into $f^\prime(x)$. So $m=f^\prime(5)=2\times5 = 10$.

Step3: Find the equation of the tangent line

Use the point - slope form of a line $y - y_{1}=m(x - x_{1})$, where $(x_{1},y_{1})=(5,26)$ and $m = 10$. $y-26=10(x - 5)$ $y-26=10x-50$ $y=10x - 24$

Answer:

The slope of the function's graph at the given point is $m = 10$. The equation of the tangent line is $y=10x - 24$.