find the terminal point on the unit circle determined by $\\frac{5\\pi}{6}$ radians. use exact values, not…

find the terminal point on the unit circle determined by $\\frac{5\\pi}{6}$ radians. use exact values, not decimal approximations. $(x,y)=(\\square,\\square)$

find the terminal point on the unit circle determined by $\\frac{5\\pi}{6}$ radians. use exact values, not decimal approximations. $(x,y)=(\\square,\\square)$

Answer

Explanation:

Step1: Recall the formula for terminal point on unit circle

For a unit circle (x = \cos\theta) and (y=\sin\theta), where (\theta=\frac{5\pi}{6})

Step2: Find the value of (x)

(\cos\frac{5\pi}{6}=\cos(\pi - \frac{\pi}{6})=-\cos\frac{\pi}{6}=-\frac{\sqrt{3}}{2})

Step3: Find the value of (y)

(\sin\frac{5\pi}{6}=\sin(\pi - \frac{\pi}{6})=\sin\frac{\pi}{6}=\frac{1}{2})

Answer:

((x,y)=\left(-\frac{\sqrt{3}}{2},\frac{1}{2}\right))