find the value of x where the given function has a vertical asymptote.\nf(x) = \\frac{1}{x - 3}\nx = ?
find the value of x where the given function has a vertical asymptote.\nf(x) = \\frac{1}{x - 3}\nx = ?
Answer
Explanation:
Step1: Recall vertical - asymptote condition
A rational function $y = \frac{f(x)}{g(x)}$ has a vertical asymptote at $x = a$ when $g(a)=0$ and $f(a)\neq0$. For the function $f(x)=\frac{1}{x - 3}$, we set the denominator equal to zero. $x-3 = 0$
Step2: Solve for x
Add 3 to both sides of the equation $x-3 = 0$. $x=3$
Answer:
$x = 3$