find the value of each limit.\n1. $lim_{x\to - 3}(2x^{2}+x - 5)$

Explanation:

Step1: Substitute x = - 3

Substitute x=-3 into the expression $2x^{2}+x - 5$. $2(-3)^{2}+(-3)-5$

Step2: Calculate powers

Calculate $(-3)^{2}=9$. $2\times9+(-3)-5$

Step3: Perform multiplications

$2\times9 = 18$. $18-3 - 5$

Step4: Perform subtractions

$18-3=15$, then $15 - 5=10$.

Answer:

$10$