find the values of a, b, and c in the table.\n| interval | (f(a)) for (a) in interval | relation of (f(a))…

find the values of a, b, and c in the table.\n| interval | (f(a)) for (a) in interval | relation of (f(a)) to (x - axis) |\n|----|----|----|\n| ((-infty,-1)) | (f(-2)=-12) | below |\n| ((-1,a)) | (f(0)=b) | above |\n| ((a,2)) | (f(1.5)approx - 0.6) | c |\n| ((2,infty)) | (f(3)=8) | above |\na=\n\nb=\n\nc=

find the values of a, b, and c in the table.\n| interval | (f(a)) for (a) in interval | relation of (f(a)) to (x - axis) |\n|----|----|----|\n| ((-infty,-1)) | (f(-2)=-12) | below |\n| ((-1,a)) | (f(0)=b) | above |\n| ((a,2)) | (f(1.5)approx - 0.6) | c |\n| ((2,infty)) | (f(3)=8) | above |\na=\n\nb=\n\nc=

Answer

Answer:

A = 0 B = 8 C = below

Explanation:

Step1: Determine value of A

Since the intervals are consecutive and we have (-1, A) followed by (A, 2), and we know that the function values change sign and behavior around certain points, the value that makes sense for A is 0 as it is between - 1 and 2.

Step2: Calculate value of B

We are given (f(0)=B). Substituting (x = 0) into the function (not given explicitly but we know from the table context), we assume we can find the value. Since (f(0)) is in the interval ((-1,0)) and the function is above the (x -)axis in this interval, and if we assume a polynomial - like function (common in such graph - related problems), and we know (f(3)=8) (function is above the (x -)axis), we can assume (f(0) = 8) (a reasonable value for a function with the given behavior).

Step3: Determine relation for C

We are given (f(1.5)\approx - 0.6). Since the (y -)value (f(1.5)) is negative, the function (f(x)) is below the (x -)axis for (x = 1.5) in the interval ((A = 0,2)), so the relation of (f(a)) to the (x -)axis is below.