find the vertex.\nf(x) = 3x² - 6x + 2\n(?, )

Explanation:

Step1: Find x-coordinate of vertex

For quadratic $ax^2+bx+c$, $x=-\frac{b}{2a}$. Here $a=3$, $b=-6$, so: $x=-\frac{-6}{2\times3}=\frac{6}{6}=1$

Step2: Find y-coordinate of vertex

Substitute $x=1$ into $f(x)$: $f(1)=3(1)^2-6(1)+2=3-6+2=-1$

Answer:

$(1, -1)$