find the vertical asymptote.\ny = \\frac{3x - 3}{x + 1}\nx = ?

Answer:

$x=-1$

Explanation:

Step1: Recall vertical - asymptote rule

A vertical asymptote of a rational function $y = \frac{f(x)}{g(x)}$ occurs where $g(x)=0$.

Step2: Set the denominator equal to 0

For $y=\frac{3x - 3}{x + 1}$, set $x + 1=0$.

Step3: Solve for x

$x=-1$.