find the vertical asymptote.\ny = \\frac{3x + 27}{x - 9}\nx = ?

find the vertical asymptote.\ny = \\frac{3x + 27}{x - 9}\nx = ?

find the vertical asymptote.\ny = \\frac{3x + 27}{x - 9}\nx = ?

Answer

Explanation:

Step1: Recall vertical - asymptote rule

Vertical asymptotes occur where the denominator of a rational function is zero and the numerator is non - zero. Set the denominator equal to zero: $x - 9=0$.

Step2: Solve for x

Add 9 to both sides of the equation $x - 9=0$. $x=9$. We check the numerator at $x = 9$. Substitute $x = 9$ into the numerator $3x+27$: $3\times9 + 27=27 + 27=54\neq0$.

Answer:

$x = 9$