find the vertical asymptote.\ny = \\frac{4x + 12}{4x - 12}\nx = ?

find the vertical asymptote.\ny = \\frac{4x + 12}{4x - 12}\nx = ?

find the vertical asymptote.\ny = \\frac{4x + 12}{4x - 12}\nx = ?

Answer

Explanation:

Step1: Recall vertical - asymptote rule

Vertical asymptotes occur where the denominator of a rational function is zero. Set the denominator equal to zero: $4x - 12=0$.

Step2: Solve the equation for x

Add 12 to both sides: $4x=12$. Then divide both sides by 4: $x = \frac{12}{4}=3$.

Answer:

$x = 3$