find the vertical asymptote(s) of the graph of the function.\ng(x)=\\frac{1}{(x - 3)^2}\nselect the correct…

find the vertical asymptote(s) of the graph of the function.\ng(x)=\\frac{1}{(x - 3)^2}\nselect the correct choice below and, if necessary, fill in the answer box(es) to complete your choice.\n○ a. the function has one vertical asymptote, \n(type an equation.)\n○ b. the function has two vertical asymptotes. the leftmost asymptote is and the rightmost asymptote is \n(type equations.)\n○ c. the function has no vertical asymptotes.

find the vertical asymptote(s) of the graph of the function.\ng(x)=\\frac{1}{(x - 3)^2}\nselect the correct choice below and, if necessary, fill in the answer box(es) to complete your choice.\n○ a. the function has one vertical asymptote, \n(type an equation.)\n○ b. the function has two vertical asymptotes. the leftmost asymptote is and the rightmost asymptote is \n(type equations.)\n○ c. the function has no vertical asymptotes.

Answer

Explanation:

Step1: Recall the definition of vertical asymptote

A vertical asymptote occurs at (x = a) if the denominator of a rational function is zero at (x = a) and the numerator is non - zero at (x = a). For the function (g(x)=\frac{1}{(x - 3)^2}), set the denominator equal to zero: ((x - 3)^2=0).

Step2: Solve the equation for (x)

Take the square root of both sides of the equation ((x - 3)^2=0). We get (x-3 = 0), so (x = 3). The numerator is (1), and when (x = 3), the numerator (1\neq0).

Answer:

A. The function has one vertical asymptote, (x = 3).