find all vertical asymptotes of the following function.\nf(x)=\frac{x^{2}+4x - 32}{3x + 30}

Answer:

$x = - 10$

Explanation:

Step1: Set the denominator equal to 0.

$3x + 30=0$

Step2: Solve the equation for x.

$3x=-30$ $x = - 10$ Since the numerator $x^{2}+4x - 32=(x + 8)(x - 4)$ is non - zero when $x=-10$, $x = - 10$ is a vertical asymptote.