follow the step - by - step process in parts a through c to determine the difference quotient…

follow the step - by - step process in parts a through c to determine the difference quotient, $f(x)=2x^{2}+5x - 3$. a. determine $f(x + h)$. $f(x + h)=square$ (simplify your answer. do not factor.) b. simplify the expression $f(x + h)-f(x)$. $f(x + h)-f(x)=square$ (simplify your answer. do not factor.) c. determine the difference quotient $\frac{f(x + h)-f(x)}{h}$.
Answer
Explanation:
Step1: Find f(x + h)
Substitute (x+h) into (f(x)): [ \begin{align*} f(x + h)&=2(x + h)^2+5(x + h)-3\ &=2(x^{2}+2xh+h^{2})+5x + 5h-3\ &=2x^{2}+4xh+2h^{2}+5x + 5h-3 \end{align*} ]
Step2: Find f(x + h)-f(x)
[ \begin{align*} f(x + h)-f(x)&=(2x^{2}+4xh+2h^{2}+5x + 5h-3)-(2x^{2}+5x - 3)\ &=2x^{2}+4xh+2h^{2}+5x + 5h-3 - 2x^{2}-5x + 3\ &=4xh+2h^{2}+5h \end{align*} ]
Step3: Find the difference quotient (\frac{f(x + h)-f(x)}{h})
[ \begin{align*} \frac{f(x + h)-f(x)}{h}&=\frac{4xh+2h^{2}+5h}{h}\ &=\frac{h(4x + 2h+5)}{h}\ &=4x+2h + 5 \end{align*} ]
Answer:
a. (2x^{2}+4xh+2h^{2}+5x + 5h-3) b. (4xh+2h^{2}+5h) c. (4x+2h + 5)