4. which of the following functions will result with a value of 1/2? (0.5 point) a sin(9π/2) b cos(19π/6) c…

4. which of the following functions will result with a value of 1/2? (0.5 point) a sin(9π/2) b cos(19π/6) c sin(-17π/6) d cos(11π/3) 5. what are the values of each of the 6 different trigonometric functions below? (1point total) trigonometric functions value set a sin(π/6) sin(-11π/6) set b cos(270°) cos(-90°) set c tan(-3π/4) tan(5π/4)
Answer
Explanation:
Step1: Simplify sin(9π/2)
$\sin\left(\frac{9\pi}{2}\right)=\sin\left(4\pi+\frac{\pi}{2}\right)=\sin\left(\frac{\pi}{2}\right) = 1$
Step2: Simplify cos(19π/6)
$\cos\left(\frac{19\pi}{6}\right)=\cos\left(2\pi + \frac{7\pi}{6}\right)=\cos\left(\frac{7\pi}{6}\right)=-\frac{\sqrt{3}}{2}$
Step3: Simplify sin(-17π/6)
$\sin\left(-\frac{17\pi}{6}\right)=-\sin\left(\frac{17\pi}{6}\right)=-\sin\left(2\pi+\frac{5\pi}{6}\right)=-\sin\left(\frac{5\pi}{6}\right)=-\frac{1}{2}$
Step4: Simplify cos(11π/3)
$\cos\left(\frac{11\pi}{3}\right)=\cos\left(4\pi-\frac{\pi}{3}\right)=\cos\left(-\frac{\pi}{3}\right)=\cos\left(\frac{\pi}{3}\right)=\frac{1}{2}$
Answer:
D. $\cos\left(\frac{11\pi}{3}\right)$
Explanation for question 5:
Step1: Find sin(π/6)
$\sin\left(\frac{\pi}{6}\right)=\frac{1}{2}$
Step2: Find sin(-11π/6)
$\sin\left(-\frac{11\pi}{6}\right)=-\sin\left(\frac{11\pi}{6}\right)=-\sin\left(2\pi - \frac{\pi}{6}\right)=\sin\left(\frac{\pi}{6}\right)=\frac{1}{2}$
Step3: Find cos(270°)
$\cos(270^{\circ}) = 0$
Step4: Find cos(-90°)
$\cos(-90^{\circ})=\cos(90^{\circ}) = 0$
Step5: Find tan(-3π/4)
$\tan\left(-\frac{3\pi}{4}\right)=-\tan\left(\frac{3\pi}{4}\right)=-\tan\left(\pi-\frac{\pi}{4}\right)=\tan\left(\frac{\pi}{4}\right)=1$
Step6: Find tan(5π/4)
$\tan\left(\frac{5\pi}{4}\right)=\tan\left(\pi+\frac{\pi}{4}\right)=\tan\left(\frac{\pi}{4}\right)=1$
Answer:
| Trigonometric Functions | Value |
|---|---|
| $\sin\left(\frac{\pi}{6}\right)$ | $\frac{1}{2}$ |
| $\sin\left(-\frac{11\pi}{6}\right)$ | $\frac{1}{2}$ |
| $\cos(270^{\circ})$ | $0$ |
| $\cos(-90^{\circ})$ | $0$ |
| $\tan\left(-\frac{3\pi}{4}\right)$ | $1$ |
| $\tan\left(\frac{5\pi}{4}\right)$ | $1$ |