$$ f ( x ) = \\frac { \\sin ( x ) } { x } $$\nhow would you rewrite $$ f ( x ) $$ so it can be…

$$ f ( x ) = \\frac { \\sin ( x ) } { x } $$\nhow would you rewrite $$ f ( x ) $$ so it can be differentiated using the\npower rule?\nassume $$ x \\neq 0 $$.\nchoose 1 answer:\na $$ x ^ { - 1 } \\sin ( x ) $$\nb $$ \\sin ( x ) \\cdot \\frac { 1 } { - } $$

$$ f ( x ) = \\frac { \\sin ( x ) } { x } $$\nhow would you rewrite $$ f ( x ) $$ so it can be differentiated using the\npower rule?\nassume $$ x \\neq 0 $$.\nchoose 1 answer:\na $$ x ^ { - 1 } \\sin ( x ) $$\nb $$ \\sin ( x ) \\cdot \\frac { 1 } { - } $$

Answer

Explanation:

Step1: Recall the negative exponent rule

The negative exponent rule states that (a^{-n}=\frac{1}{a^{n}}) for (a\neq0) and integer (n). Here, (\frac{1}{x}=x^{- 1}) since (n = 1).

Step2: Rewrite the function

Given (f(x)=\frac{\sin(x)}{x}), using the negative - exponent rule, we can rewrite it as (f(x)=x^{-1}\sin(x))

Answer:

A. (x^{-1}\sin(x))