the function f(x)=1.1x^3 - 33x^2 + 260x + 564 below models the number of discharges from the military, f(x)…

the function f(x)=1.1x^3 - 33x^2 + 260x + 564 below models the number of discharges from the military, f(x), of active - duty gay service members under the \dont ask, dont tell\ policy x years after 1994. complete parts a and b.\nthe slope of the secant line is 146. (round to the nearest whole number as needed.)\nb. the actual average yearly increase from 1994 to 1998 was 140. does the slope from part (a) underestimate or overestimate this value? by how much?\nthe slope from part (a) overestimates the actual average yearly increase.\nthe slope from part (a) differs from the actual average yearly increase by 5.9

the function f(x)=1.1x^3 - 33x^2 + 260x + 564 below models the number of discharges from the military, f(x), of active - duty gay service members under the \dont ask, dont tell\ policy x years after 1994. complete parts a and b.\nthe slope of the secant line is 146. (round to the nearest whole number as needed.)\nb. the actual average yearly increase from 1994 to 1998 was 140. does the slope from part (a) underestimate or overestimate this value? by how much?\nthe slope from part (a) overestimates the actual average yearly increase.\nthe slope from part (a) differs from the actual average yearly increase by 5.9

Answer

Explanation:

Step1: Identify given values

Slope of secant line from part (a) is 146, actual average yearly increase is 140.

Step2: Compare values

To find if it over - or under - estimates, subtract actual value from slope of secant line: $146−140 = 6$.

Answer:

The slope from part (a) overestimates the actual average yearly increase. The slope from part (a) differs from the actual average yearly increase by 6.