which function is graphed below?\no $f(x)=\\cos(x)$\no $f(x)=-\\cos(x)$\no $f(x)=\\sin(x)$\no $f(x)=-\\sin(x)$
which function is graphed below?\no $f(x)=\\cos(x)$\no $f(x)=-\\cos(x)$\no $f(x)=\\sin(x)$\no $f(x)=-\\sin(x)$
Answer
Explanation:
Step1: Recall key - points of trigonometric functions
The cosine function (y = \cos(x)) has a value of (1) at (x = 0), (y=\cos(0)=1), and (y = \cos(\pi)=- 1), (y=\cos(2\pi)=1). The sine function (y=\sin(x)) has a value of (0) at (x = 0), (y=\sin(0)=0), (y=\sin(\pi)=0), (y=\sin(2\pi)=0).
Step2: Analyze the given graph
The graph has a value of (1) at (x = 0), so it is a cosine - type function. Since the graph is reflected about the (x) - axis (it starts at (y = 1) and then goes down to (y=-1) at (x=\pi)), the function is (y =-\cos(x)).
Answer:
(f(x)=-\cos(x))