geraldine is asked to explain the limits on the range of an exponential equation using the function…

geraldine is asked to explain the limits on the range of an exponential equation using the function (f(x)=2^{x}). she makes these two statements. 1. as (x) increases infinitely, the (y - values) are continually doubled for each single increase in (x). 2. as (x) decreases infinitely, the (y - values) are continually halved for each single decrease in (x). she concludes that there are no limits within the set of real numbers on the range of this exponential function. which best explains the accuracy of geraldines statements and her conclusion? statement 1 is incorrect because the (y - values) are increased by 2, not doubled. statement 2 is incorrect because the (y - values) are doubled, not halved. the conclusion is incorrect because the range is limited to the set of integers. the conclusion is incorrect because the range is limited to the set of positive real numbers.

geraldine is asked to explain the limits on the range of an exponential equation using the function (f(x)=2^{x}). she makes these two statements. 1. as (x) increases infinitely, the (y - values) are continually doubled for each single increase in (x). 2. as (x) decreases infinitely, the (y - values) are continually halved for each single decrease in (x). she concludes that there are no limits within the set of real numbers on the range of this exponential function. which best explains the accuracy of geraldines statements and her conclusion? statement 1 is incorrect because the (y - values) are increased by 2, not doubled. statement 2 is incorrect because the (y - values) are doubled, not halved. the conclusion is incorrect because the range is limited to the set of integers. the conclusion is incorrect because the range is limited to the set of positive real numbers.

Answer

Explanation:

Step1: Analyze statement 1

For the function $f(x)=2^{x}$, when $x$ increases by 1 (from $x$ to $x + 1$), $f(x+1)=2^{x + 1}=2\times2^{x}=2f(x)$. So as $x$ increases infinitely, the $y -$values are continually doubled for each single increase in $x$. Statement 1 is correct.

Step2: Analyze statement 2

When $x$ decreases by 1 (from $x$ to $x - 1$), $f(x - 1)=2^{x-1}=\frac{2^{x}}{2}$. So as $x$ decreases infinitely, the $y -$values are continually halved for each single decrease in $x$. Statement 2 is correct.

Step3: Analyze the range

The function $y = 2^{x}$, for all real - valued $x$, $y=2^{x}>0$. The range of the function $y = 2^{x}$ is the set of positive real numbers, not all real numbers. So the conclusion is incorrect.

Answer:

The conclusion is incorrect because the range is limited to the set of positive real numbers.