give the derivative formula for the function.\ng(x) = 2.9^x + π^2\ng(x) =

Explanation:

Step1: Recall derivative rules

The derivative of $a^x$ is $a^x\ln(a)$ and the derivative of a constant is 0.

Step2: Differentiate each term

For the first - term $2.9^x$, its derivative is $2.9^x\ln(2.9)$ according to the rule $\frac{d}{dx}(a^x)=a^x\ln(a)$ with $a = 2.9$. For the second - term $\pi^2$, since $\pi^2$ is a constant, its derivative is 0.

Step3: Combine the derivatives

$g'(x)$ is the sum of the derivatives of the two terms. So $g'(x)=2.9^x\ln(2.9)+0$.

Answer:

$2.9^x\ln(2.9)$