(a) give the x - value of a point where the slope of the tangent line for h(x) is positive.\nx = \n(b) give…

(a) give the x - value of a point where the slope of the tangent line for h(x) is positive.\nx = \n(b) give the x - value of a point where the slope of the tangent line for h(x) is negative.\nx = \n(c) give the x - value for all of the points where the slope of the tangent line for h(x) is zero.\nx = (separate answers with a comma)
Answer
Explanation:
Step1: Recall slope - tangent relationship
The slope of the tangent line to a function $y = h(x)$ at a point is given by the derivative $h'(x)$. If $h'(x)>0$, the function is increasing; if $h'(x)<0$, the function is decreasing; if $h'(x) = 0$, the function has a horizontal tangent.
Step2: Analyze increasing part for (a)
Looking at the graph, the function $h(x)$ is increasing (slope of tangent is positive) for $x>2$. We can choose $x = 3$.
Step3: Analyze decreasing part for (b)
The function $h(x)$ is decreasing (slope of tangent is negative) for $0<x<2$. We can choose $x = 1$.
Step4: Analyze horizontal - tangent part for (c)
The function $h(x)$ has horizontal tangents (slope of tangent is zero) at the local maximum and local minimum points. From the graph, these occur at $x = 0$ and $x = 2$.
Answer:
(a) $x = 3$ (b) $x = 1$ (c) $x = 0,2$