given $f(x) = 3x + 1$, solve for $x$ when $f(x) = 7$.

given $f(x) = 3x + 1$, solve for $x$ when $f(x) = 7$.

given $f(x) = 3x + 1$, solve for $x$ when $f(x) = 7$.

Answer

Explanation:

Step1: Substitute f(x) with 7

We know that ( f(x) = 3x + 1 ) and ( f(x) = 7 ), so we substitute to get ( 7 = 3x + 1 ).

Step2: Subtract 1 from both sides

Subtract 1 from each side: ( 7 - 1 = 3x + 1 - 1 ), which simplifies to ( 6 = 3x ).

Step3: Divide both sides by 3

Divide both sides by 3: ( \frac{6}{3} = \frac{3x}{3} ), so ( x = 2 ).

Answer:

( x = 2 )